Monaejackson1044 Monaejackson1044

17-12-2017
Chemistry

contestada

A sample of gas (24.2 g) initially at 4.00 atm was compressed from 8.00 l to 2.00 l at constant temperature. after the compression, the gas pressure was __________ atm

Respuesta :

29-12-2017

Answer: 16 atm
Explanation:
P1V1 = P2V2
P2 = P1V1/V2
=4 atm x 8.00 L/2.00L = 16 atm

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