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  • 21-01-2018
  • Mathematics
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Find dy/dx when y = cosh (bx^2}

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Find dydx when y cosh bx2 Pic below class=

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carlosego
carlosego carlosego
  • 21-01-2018
y = cosh (bx^2} 
 dy/dx= sin
h (bx^2}*( bx^2)'
 dy/dx= sinh (bx^2}*( 2bx)
 answer
 sinh (bx^2}*( 2bx)
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