The answer is
x+1, x+2, x+3, x+4 and x+5.
The sum of these six integers is 393 so we can write:
x+x+1+x+2+x+3+x+4+x+5=393
6x+1+2+3+4+5=393
6x+15=393
6x+15−15=393−15
6x+0=378
6x6=3786
x=63
Because the first integer is 63 then the third would be x+2 or 63+2=65
Hope its helps :)
