itsmaddierae12
itsmaddierae12 itsmaddierae12
  • 20-02-2018
  • Mathematics
contestada

Can someone please help me with 4?? I’m really struggling.

Can someone please help me with 4 Im really struggling class=

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s1m1
s1m1 s1m1
  • 20-02-2018
4) given is that
m<DAC=y
m<BAC=3x

ABCD is a square so m<DAB = 90° because each angle in a square is a right angle so 3x+y=90° (1) ;
AC is a diagonal in the square so m<DAC=m<BAC so 3x=y (2);

Find x by substituting y to 3x from (2) into (1)
3x+3x=90
6x=90
x=90/6=15°

Answer x=15°


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