Respuesta :

[tex]\bf sin(2x)-1=0\implies sin(2x)=1\implies sin^{-1}[sin(2x)]=sin^{-1}(1) \\\\\\ 2x=sin^{-1}(1)\implies 2x=\cfrac{\pi }{2}\implies x=\cfrac{\pi }{4}\textit{ which is }45^o[/tex]

Otras preguntas