Respuesta :

[tex] \frac{4(3x^{2}y^{4})^{3}}{(2x^{3}y^{5})^{4}} = \frac{4* ( 3^{3} x^{6} y^{12}) }{2^4 x^{12} y^{20}} = \frac{108}{16x^{6} y^{8} } = \frac{27}{4 x^{6} y^{8} } [/tex]

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