[tex]\text{Total area}=\text{A}_{\text{parallelogram}}+\text{A}_{\text{triangle}}\\\\
\text{A}_{\text{parallelogram}}=\text{base }\times\text{ height}=20\times16=320\;\text{in}^2\\\\
\text{A}_{\text{triangle}}=\dfrac{\text{base}\times\text{height}}{2}=\dfrac{8\times16}{2}=\dfrac{128}{2}=64\text{ in}^2\\\\
\text{Total area}=320+64=384\text{ in}^2[/tex]
