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Which function has a vertex at (2, –9)? f(x) = –(x – 3)2 f(x) = (x + 8)2 f(x) = (x – 5)(x + 1) f(x) = –(x – 1)(x – 5)

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scorpiontank01
Answer is F(x)=(x-5)(x+1)

How? Plugged the functions into a graphing calculator until I found the correct vertex that is assuming the 2s were exponents on question a and b.

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