I'm going to assume that you meant the equation to be: [tex] h(x)=-5x-10 [/tex]
So we're going to take that equation and we're going to solve for h(-2).
This means that we plug in a '-2' for every x in the equation:
[tex] h(-2)=-5x-10 [/tex]
[tex] h(-2)=-5(-2)-10 [/tex]
[tex] h(-2)=10-10 [/tex]
[tex] h(-2)=0 [/tex]
So when we solve the equation for h(-2), we get 0 as our answer.
