Respuesta :

[tex]\bf \textit{exponential form of a logarithm} \\\\ log_a b=y \implies a^y= b\qquad\qquad % exponential notation 2nd form a^y= b\implies log_a b=y \\\\ -------------------------------\\\\ 4^2=16\implies log_4(16)=2[/tex]
The answer is 4log2=16

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