a1=25(0.3)^2, common ratio = 0.3
So sum of first n terms of a geometric series = a1(1-r^n)/(1-r)
So sum of frist 10 terms of the given series = 25(0.3)^2(1-0.3^10)/ (1-0.3)
So sum of n=2 to n=10 is : 25(0.3)^2(1=0.3^10)/(1-0.3) -25(0.3)^2= 0.96426673425
