Respuesta :

gmany

[tex]k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}[/tex]

We have: [tex]y=\dfrac{4}{5}x-3\to m_1=\dfrac{4}{5}[/tex]

substitute

[tex]m_2=-\dfrac{1}{\frac{4}{5}}=-\dfrac{5}{4}[/tex]

Answer: B. -5/4

Otras preguntas