Respuesta :

konrad509

[tex] |\Omega|=6^2=36\\
|A|=5\\\\
P(A)=\dfrac{5}{36} [/tex]

prob ( 2 then a 4) = 1/6 * 1/6 = 1/36

prob( 4 then a 2) = 1/36

Prob ( two 3's) = 1/36

Prob (1 and 5 or 5 and 1) = 1/18

So it is 3/36 + 1/18 = 3/36 + 2 /36 = 5/36 Answer

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