The area of the rectangle 4 × 19
[tex]A_1=4\cdot19=76[/tex]
The area of the rectangle 24 × 11
[tex]A_2=24\cdot11=264[/tex]
The area of the polygon:
[tex]A=a_1+A_2\\\\A=76+264=340[/tex]
Answer: B. 340 squaer units
