Respuesta :

gmany

[tex]\begin{array}{ccc}4\dfrac{1}{2}\ mi&-&\dfrac{3}{4}\ h\\\\x\ mi&-&2\ h\end{array}\ \ \ cross\ multiply\\.\\\\\dfrac{3}{4}x=2\cdot4\dfrac{1}{2}\\\\\dfrac{3}{4}x=9\ \ \ \ |\cdot\dfrac{4}{3}\\\\x=12\ mi\\\\Answer:\ 12\ mi[/tex]