9.
[tex]4 < 5 < 9[/tex]
[tex]2^2 < 5 < 3^2[/tex]
[tex]2 < \sqrt 5 < 3[/tex]
[tex]-3 < -\sqrt 5 < -2 < -1.96312...[/tex]
[tex]-\sqrt 5 < -1.96312...[/tex]
10.
The least will be one of the negative ones, -3 or -6/5. Since -6/5=-1.2, we see
-3 is the least
11.
81 < 90 < 100
[tex]9^2 < 90 < 10^2[/tex]
[tex]9 < \sqrt{90} < 10[/tex]
Answer: 10 feet
12.
We know [tex]\sqrt 8 > \sqrt 5[/tex] and [tex]2.5 > 2 \frac 1 3[/tex]
Since
[tex]2.5^2 = 6.25 < 8[/tex]
[tex] \sqrt 8 [/tex] is the tallest.
