boys (b): g + 124
girls (g): g
Total (T): b + g
I am going to set up a proportion based on boys to total students.
[tex]\frac{11}{20} = \frac{124 + g}{(124 + g) + (g)}[/tex]
⇒ [tex]\frac{11}{20} = \frac{124 + g}{124 + 2g}[/tex]
⇒ 11(124 + 2g) = 20(124 + g)
⇒ 1364 + 22g = 2480 + 20g
⇒ 1364 + 2g = 2480
⇒ 2g = 1116
⇒ g = 558
boys (b): g + 124 = (558) + 124 = 682
Total (T): b + g = 682 + 558 = 1240
Answer: 1240 total students
