Let's assume
point K as (x,y)
M is the midpoint of JK
so, other point as J(0, 11)
M(-3,2)
[tex](-3,2)=(\frac{0+x}{2},\frac{11+y}{2})[/tex]
now, we can compare both sides
Calculation of x-coordinate:
we get
[tex]-3=\frac{0+x}{2}[/tex]
[tex]x=-6[/tex]
Calculation of y-coordinate:
we get
[tex]2=\frac{11+y}{2}[/tex]
[tex]11+y=4[/tex]
[tex]y=-7[/tex]
so, we will get point K
K=(-6,-7)............Answer
