prettyonfleek35 prettyonfleek35

20-09-2018
Mathematics

contestada

use substitution to solve for k. j+2k= -4 3j-4k= 3

Respuesta :

20-09-2018

j+2k=-4
j=-4-2k (1)

3j-4k=3 (2)

Substitue (1) in (2)

3(-4-2k)-4k=3
-12-6k-4k=3
-10k=3+12
k=-15/10 (3)

Substitue (3) in (1)

j=-4-2(-15/10)
j=-1

Final answers j = -1 and k = -15/10

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