f( - [tex]\frac{1}{2})[/tex]) = [tex]\frac{16}{3}[/tex]
substitute x = - [tex]\frac{1}{2}[/tex] into f(x)
f( - [tex]\frac{1}{2}[/tex] = - [tex]\frac{2}{3}[/tex] × - [tex]\frac{1}{2}[/tex] + 5
= [tex]\frac{1}{3}[/tex] + [tex]\frac{15}{3}[/tex] = [tex]\frac{16}{3}[/tex]
