We know:
[tex]\tan\Theta=\dfrac{\sin\Theta}{\cos\Theta}[/tex]
We have:
[tex]\sin\Theta=\dfrac{\sqrt3}{2},\ \cos\Theta=\dfrac{1}{2}[/tex]
Substitute:
[tex]\tan\Theta=\dfrac{\frac{\sqrt3}{2}}{\frac{1}{2}}=\dfrac{\sqrt3}{2}:\dfrac{1}{2}=\dfrac{\sqrt3}{2}\cdot\dfrac{2}{1}=\sqrt3[/tex]
Answer: a. √3
