The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have [tex]\left(\dfrac{1}{4},\ 2\right),\ \left(3,\ \dfrac{2}{3}\right)[/tex]
Substitute:
[tex]m=\dfrac{\frac{2}{3}-2}{3-\frac{1}{4}}=\dfrac{\frac{2}{3}-\frac{6}{3}}{\frac{12}{4}-\frac{1}{4}}=\dfrac{-\frac{4}{3}}{\frac{11}{4}}=-\dfrac{4}{3}\cdot\dfrac{4}{11}=-\dfrac{16}{33}[/tex]
Answer: [tex]m=-\dfrac{16}{33}[/tex]
