C + O2= CO2
[tex]n = \frac{m}{mw} [/tex]
[tex]n = \frac{5.4}{12} \\ n = 0.45 \: mol \: of \: carbon[/tex]
[tex]n = \frac{13.6}{12 + 16 \times 2} \\ n = \frac{13.6}{44} \\ n = 0.31 \: mol \: of \: carbon \: dioxide[/tex]
CO2 is limit
5.4-3.72= 1.68 g of C is excess
5.4 g = 100%
3.72 g = x
x=68.9 %
