[tex]\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{4})~\hspace{10em} slope = m\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=\cfrac{1}{3}(x-3) \\\\\\ y-4=\cfrac{1}{3}x-1\implies y=\cfrac{1}{3}x+3[/tex]
