[tex]\dfrac{5}{12} < \boxed{\ ?\ } < \dfrac{3}{4}=\dfrac{3\cdot3}{4\cdot3}=\dfrac{9}{12}\\\\Answer:\\\\\dfrac{5}{12} <\boxed{\dfrac{6}{12}=\dfrac{1}{2}}<\dfrac{9}{12}=\dfrac{3}{4}\\\\\dfrac{5}{12}<\boxed{\dfrac{7}{12}}<\dfrac{9}{12}=\dfrac{3}{4}\\\\\dfrac{5}{12} <\boxed{\dfrac{8}{12}=\dfrac{2}{3}}<\dfrac{9}{12}=\dfrac{3}{4}[/tex]
