Answer:
0
Step-by-step explanation:
[tex]g(x) = 3x + 1 \\\ y = 3x + 1[/tex]
Changing x to y and y to x:
[tex]x = 3y + 1 \\\ 3y = x - 1 \\\ y = \frac{x - 1}{3} \\\ g^{-1}(x) = \frac{x - 1}{3} \\\ g^{- 1} (1) = \frac{1 - 1}{3} \\\ g^{- 1} (1) = 0[/tex]
I hope I helped you.
