Respuesta :

maicolmedyna

Answer:


Step-by-step explanation:

H

[tex]6x^2+3x+1=0\\a=6,b=3,c=1\\(-b+-\sqrt{b^2-4ac} )/2a\\\\\frac{-3+-\sqrt{-15} }{12} \\\\[/tex]


The roots are:

[tex]\frac{-3+-i\sqrt{15} }{12}[/tex]

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