Answer:
[tex]\text{The value of x in terms of p is }\frac{15}{p}[/tex]
The value of x is -3 when p is -5
Step-by-step explanation:
Given the equation 4(px+1)=64
we have to find the value of x in terms of p and value of x when p is -5.
4(px+1)=64
Divide throughout by 4
⇒ [tex]px+1=\frac{64}{4}=16[/tex]
Subtracting 1 from both sides,we get
[tex]px=16-1=15[/tex]
⇒ [tex]x=\frac{15}{p}[/tex]
When p=-5
[tex]x=\frac{15}{-5}=-3[/tex]
The value of x is -3 when p is -5
