Answer:
7 - i[tex]\sqrt{2}[/tex]
Step-by-step explanation:
Given a complex number a ± bi then the complex conjugate is
a ∓ bi
Note that the real part remains the same while the sign of the coefficient of the imaginary part is the opposite
Hence conjugate of 7 + i[tex]\sqrt{2}[/tex] is 7 - i[tex]\sqrt{2}[/tex]
