Answer:
perimeter = 8[tex]\sqrt{\pi }[/tex]
Step-by-step explanation:
We require to calculate the area (A) of the circle
A = πr² ← r is the radius
circumference = 4π = 2πr, hence
2πr = 4π ( divide both sides by 2π )
r = 2, hence
A = π × 4 = 4π
The area of the square is therefore 4π and area = s² ← s is the side length
s² = 4π ( take the square root of both sides )
s = [tex]\sqrt{4\pi }[/tex] = 2[tex]\sqrt{\pi }[/tex], hence
perimeter = 4 × 2[tex]\sqrt{\pi }[/tex] = 8[tex]\sqrt{\pi }[/tex]
