Answer:
f(x) = x^2 + 12x + 20
Step-by-step explanation:
What is meant is that write a function that when - 2 is put in for x, the function goes to 0.
More formally f(-2) = 0.
So the function you want is f(x) = y = (x + 2)(x + 10) which is
f(x) = x^2 + 10x + 2x + 20
f(x) = x^2 + 12x + 20
Now put - 2 into this function.
f(-2)= (-2)^2 + 12(-2) + 20
f(-2) = 4 - 24 + 20
f(-2) = 4 + 20 - 24
f(-2) = 0
I'll leave you to do the same thing with - 10
