Answer: [tex]\bold{y^{\dfrac{1}{2}}}[/tex]
Step-by-step explanation:
[tex]\bigg(x^0y^{\dfrac{1}{3}}\bigg)^{\dfrac{3}{2}}\cdot x^0\\\\\\x^0=1\\\\\\\rightarrow\ \bigg(1\cdot y^{\dfrac{1}{3}}\bigg)^{\dfrac{3}{2}}\cdot 1\\\\\\= \bigg(y^{\dfrac{1}{3}}\bigg)^{\dfrac{3}{2}}\\\\\\=y^{\dfrac{1}{3}\cdot\dfrac{3}{2}}\\\\\\=y^{\dfrac{3}{6}}\\\\=y^{\dfrac{1}{2}}[/tex]
