Answer:
see explanation
Step-by-step explanation:
Given the zero x = a of f(x) then f(a) = 0
(5)
f(9) =9³ - 8(9)² - 2(9) - 63 = 729 - 648 - 18 - 63 = 0
Hence x = 9 is a zero of the polynomial
(6)
2[tex](-3)^{4}[/tex] - 3(- 3)³ - 36(- 3)² - 37(- 3) - 26 = 162 + 81 - 324 + 111 - 26 = 4 ≠ 0
Hence x = - 3 is not a zero of the polynomial
