Answer:
Option C. [tex]132\ in^{2}[/tex]
Step-by-step explanation:
we know that
The surface area of cylinder is equal to
[tex]SA=2\pi r^{2} +\pi Dh[/tex]
we have
[tex]D=6\ in[/tex]
[tex]r=6/2=3\ in[/tex]
[tex]h=4\ in[/tex]
substitute
[tex]SA=2\pi (3^{2}) +\pi (6*4)=42\pi\ in^{2}=132\ in^{2}[/tex]
