Answer:
[tex]\large\boxed{\dfrac{1}{18}}[/tex]
Step-by-step explanation:
[tex]a^{-n}=\dfrac{1}{a^n}[/tex]
[tex]\text{Put}\ x=3\ \text{and}\ y=-2\ \text{to the expression}\ 2x^{-2}y^{-2}:\\\\2(3^{-2})(-2)^{-2}=2\left(\dfrac{1}{3^2}\right)\left(\dfrac{1}{(-2)^2}\right)=2\left(\dfrac{1}{9}\right)\left(\dfrac{1}{4}\right)=\dfrac{2}{36}=\dfrac{1}{18}[/tex]
