The launch site for trigon balloon co. is 250 ft above sea level. A hot air balloon is launched from the site and begins to rise at a rate of 110 ft/min. At the same time, another balloon 2200 ft above sea level begins to descend at a rate of 150 ft/min. A. How long will it be unit the balloons are at the same elevation? B. What will their elevation be then?
Set up the equations as equal: 110x+250=-150x+2200 Add 150x to both sides: 260x+250=2200 Subtract 250 from both sides. 260x=1950 Divide both sides by 260. x=7.5 A: They will meet at 7.5 minutes after launch Plug in 7.5: 110(7.5)+250=11*75+250=825+250=1075 B: They will meet at 1075 feet
