1.) (f + g)(x) = f (x) + g(x)
= [3x + 2] + [4 – 5x]
= 3x + 2 + 4 – 5x
= 3x – 5x + 2 + 4
= –2x + 6
2.) (f × g)(x) = [f (x)][g(x)]
= (3x + 2)(4 – 5x)
= 12x + 8 – 15x2 – 10x
= –15x2 + 2x + 8
(
f
g
)
(
x
)
=
f
(
x
)
g
(
x
)
(
g
f
)(x)=
g(x)
f(x)
=
3
x
+
2
4
−
5
x
=
4−5x
3x+2
