Respuesta :

tramserran

Answer:   [tex]\bold{\dfrac{1}{y^3}}[/tex]

Step-by-step explanation:

[tex]\dfrac{y^{-5}}{y^{-2}}\quad =\dfrac{y^{-5+5}}{y^{-2+5}}\quad =\dfrac{y^0}{y^3}\quad =\large\boxed{\dfrac{1}{y^3}}[/tex]

Answer:

[tex]\frac{1}{y^{3} }[/tex]

Step-by-step explanation:

Using the rule of exponents

• [tex]\frac{a^{m} }{a^{n} }[/tex] ⇔ [tex]\frac{1}{a^{(n-m)} }[/tex] → n > m

Hence

[tex]\frac{y^{-5} }{y^{-2} }[/tex] = [tex]\frac{1}{y^{(-2-(-5))} }[/tex] = [tex]\frac{1}{y^{3} }[/tex]