Answer:
[tex]\large\boxed{\dfrac{x}{x^2-36}-\dfrac{6}{x^2-36}=\dfrac{1}{x+6}}[/tex]
Step-by-step explanation:
[tex]\dfrac{x}{x^2-36}-\dfrac{6}{x^2-36}=\dfrac{x-6}{x^2-36}=\dfrac{x-6}{x^2-6^2}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x-6}{(x-6)(x+6)}\\\\\text{cancel}\ (x-6)\\\\=\dfrac{1}{x+6}[/tex]
