Answer:
[tex]\boxed{y=1}[/tex]
Step-by-step explanation:
Since [tex]m\angle1=m\angle2[/tex] due to [tex]\over{VP}[/tex] is an angle bisector, we have the following:
[tex]m\angle1+m\angle2=m\angle XVW\\(1+28y)+(1+28y)=59y-1\\2+56y=59y-1\\2+1=59y-56y\\3=3y\\y=1[/tex]
