jsjus jsjus
  • 17-04-2019
  • Mathematics
contestada


[tex]461 \div 1.1.[/tex]
​

tex461 div 11tex class=

Respuesta :

gmany
gmany gmany
  • 03-08-2019

Answer:

[tex]\large\boxed{19\dfrac{17}{20}}[/tex]

Step-by-step explanation:

[tex]\text{First step:}\\\\\text{Find LCD}\ (Least\ Common\ Denominator)\\\\LCD=20\\\\4\cdot5=20\\5\cdot4=20\\\\\dfrac{1}{4}=\dfrac{1\cdot5}{4\cdot5}=\dfrac{5}{20}\\\\\dfrac{3}{5}=\dfrac{3\cdot4}{5\cdot4}=\dfrac{12}{20}\\\\9\dfrac{1}{4}+10\dfrac{3}{5}=9\dfrac{5}{20}+10\dfrac{12}{20}=(9+10)+\dfrac{5+12}{20}=19\dfrac{17}{20}[/tex]

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