Answer: 30 degrees or π/6
Step-by-step explanation:
[tex]\sqrt{3} sec(\theta)-2=0\\\sqrt{3} sec(\theta)=2\\sec(\theta)=\frac{2}{\sqrt{3} } \\sec(\theta)=\frac{1}{cos(\theta)} \\cos(\theta)=\frac{\sqrt{3} }{2} \\So, \theta=30^o \\or\frac{\pi }{6}[/tex]
