kennedybrock7121 kennedybrock7121
  • 18-04-2019
  • Mathematics
contestada

The rectangle below has an area of 12y^2+21y^5 square meters The width of the rectangle (in meters) is equal to the gcf of 12y^2 and 21y^5

Respuesta :

gmany
gmany gmany
  • 27-04-2019

Answer:

length = (4+7y³)

width = 3y²

Step-by-step explanation:

[tex]12y^2=3y^2\cdot4\\\\21y^5=3y^2\cdot7y^3\\\\GCF(12y^2,\ 21y^5)=3y^2\leftarrow width\\\\\text{The formula of an area of a rectangle:}\\\\A=lw\\\\l-length\\w-width\\\\\text{We have the area of the rectangle:}\ A=12y^2+21y^5=3y^2(4+7y^3)\\\\\text{Conclusion:}\\\\length=\\width=3y^2[/tex]

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