Answer:
x-y-3=0
Step-by-step explanation:
The slope of the line that passes through the points (0,-3) and (3,0) is
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}\\ \\=\dfrac{0-(-3)}{3-0}\\ \\=\dfrac{3}{3}\\ \\=1[/tex]
The equation of the line is
[tex]y=m(x-x_1)+y_1\\ \\y=1\cdot (x-0)+(-3)\\ \\y=x-3\\ \\x-y-3=0[/tex]
