Respuesta :

gmany

Answer:

[tex]\large\boxed{y-1=-4(x+3)}[/tex]

Step-by-step explanation:

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

We have m = -4 and the point (-3, 1). Substitute:

[tex]y-1=-4(x-(-3))\\\\y-1=-4(x+3)[/tex]

Answer:

y-1=-4[x-(-3)]

Step-by-step explanation:

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