Answer:
[tex]\large\boxed{4\pi\ cm\approx12.56\ cm}[/tex]
Step-by-step explanation:
The formula of a length of an arc:
[tex]\dfrac{\pi\alpha r}{180^o}[/tex]
We have
[tex]\alpha=120^o\\\\r=6\ cm[/tex]
Substitute:
[tex][tex]\hat{MN}=\dfrac{\pi(120)(6)}{180}=4\pi\ cm\approx4(3.14)=12.56\ cm[/tex]
