Answer:
[tex]\boxed{\text{160 ft}}[/tex]
Step-by-step explanation:
The angle of depression from the ranger at point A and the angle of elevation from the fire on the ground at Point C are congruent (interior opposite angles).
The distance from the ranger up in the tower to the fire on the ground is the hypotenuse AC of the right triangle ABC.
sin 30 = 80/AC
AC = 80/sin30 = 80/0.5 = 160 ft
The distance is [tex]\boxed{\textbf{160 ft}}[/tex]
