Answer:
4
Step-by-step explanation:
The sum of the measures of all interior angles in triangle is always equal to 180°. So,
∠A+∠B+∠C=180°
∠B=180°-63°-49°=68°
Now use the sine rule:
[tex]\dfrac{c}{\sin \angle C}=\dfrac{b}{\sin \angle B}\\ \\\dfrac{3}{\sin 49^{\circ}}=\dfrac{b}{\sin 68^{\circ}}\\ \\b=\dfrac{3\sin 68^{\circ}}{\sin 49^{\circ}}\approx 3.685\approx 4[/tex]
