Answer:
if x= -1 then its is NOT in the domain of h.
Step-by-step explanation:
Domain is the set of values for which the function is defined.
we are given the function
[tex]h(x) =\frac{x+1}{x^2 + 2x + 1}[/tex]
Solving the denominator by factorization
[tex]h(x) =\frac{x+1}{x^2 + x+x + 1}\\h(x) =\frac{x+1}{x(x+1)+1(x + 1)}\\h(x) =\frac{x+1}{(x+1)(x+1)}\\h(x) =\frac{1}{(x+1)}[/tex]
So, if x = -1 then its is NOT in the domain of h.
