Answer:
[tex]x < 10[/tex]
Step-by-step explanation:
[tex]2x - 8 < 12 \\ 2x - 8 + 8 < 12 + 8 \\( 2x < 20) \div 2 = x < 10[/tex]
x<10
To solve this problem, add 8 from both sides and divide by 2 from both sides.
2x-8+8<12+8
2x<20
2x/2<20/2
20/2=10
x<10 is the correct answers.
